- #1
Glenboro
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Homework Statement
A bullet is shot vertically into the air at a speed of 512 m/s.
1) To what maximum height does the bullet go?
2) How much time passes before the bullet stops rising?
3) What is the velocity of the bullet after 60.0 s?[/B]
Homework Equations
1) V2²=V1²+2ad
2) a= (V2-V1)/Δt
3) V2=V1+aΔt
The Attempt at a Solution
1)512^2 = 0^2 + (2)(9.8)(d)
262144 = (19.6)d
262144/19.6 = d
D = 13374. 694m (My teachers says it has too many digit, so should I change to 1.33 X 10^4m ?)
2) T= (0 m/s - 512m/s)/9.8 m/s^2
T = 52.24 s
3) Vf = 512 m/s + (-9.8m/s^2)(60)
Vf = 512 - 588
V2 = 76 m/s^2 downward or opposition direction ( my teacher mentioned about significant digits, so should answer must written as 76.0 m/s^2 ?)
[/B]