- #1
Jerry
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Homework Statement
"A rock is dropped off a cliff into the water below. The sound of the splash is heard 3.0 s later. If the speed of sound is 332 m/s, calculate the height of the cliff above the water. (Note: the total time it takes for the rock to fall and the sound to travel upwards is 3.0 s)"
Therefore,
v1 = 0
g = 9.8 m/s2
Δt = 3.0 s
vsound = 332 m/s
Homework Equations
FOR SOUND
Δd = vsound * Δt2, where Δt2 is the time it takes from the sound to reach the top of the cliff from the bottom.
FOR ROCK
Δd = v1 * Δt + 0.5 * g * (Δt)2
*the following equations may be useful but i doubt it*
v2 = v1 + g * Δt
(v2)2 = (v1)2 + 2 * g * Δd
*assume no air resistance
The Attempt at a Solution
Δd = ?
No clue.
I figured that the answer should be 41 m, I believe, by trial and error but I would like to know how this can be solved in a normal way.