How High is the Coefficient of Static Friction for a Drag Car's Tires?

In summary: At first glance, the two situations might seem quite different, but in reality they both have a constant acceleration component. The equation for objects with constant acceleration is d = vt, where v is the object's velocity. In both cases, the velocity is increasing (due to the acceleration). However, the apple falls freely while the car is accelerating, and so the acceleration has a bigger impact on the apple since it's moving faster.
  • #1
liljediboi
28
0
a drag car's tires have some of the highest friction coefficients, so the book says.

it takes 6 s to go a quarter mile (about 402.5m) with constant acceleration, no skidding

what is the coefficient for the static friction?

A CORRECTION HAS BEEN MADE, IT IS 402.5m NOT 602.5
 
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  • #2
is it 1.14?
 
  • #3
You need more information to solve this problem, maybe the mass of the car. Atleast I think this problem is unsolvable based on the information you gave us.
 
  • #4
First, we need to know the amount of acceleration that makes the car travels 602.5 m in 6 s (starting from zero velocity, I presume). Using d = 0.5 at^2, we get a = 33.47 m/s/s.

If the car has mas M, then the force that makes the car accelerates as much as 33.47 m/s/s is Ma. But that Ma is the friction force (static) between the tires and the road (Since no other force could cause it). Since Ffriction = uN where N is the normal force and u is the coefficient of static friction, and since N equals to Mg where g is gravity, then

Ffriction= uN
Ma = u Mg
a = ug
u = a/g
u = 33.47/9.8
u = 3.41

Correct me if I'm wrong...
 
  • #5
umm.. the equation is d=at, not d=at^2 that's for falling objects. isint it?
 
  • #6
It is true that d = 0.5*at^2 is the equation for falling objects with zero initial velocity. More generally, it is the equation of motion for objects with constant acceleration and zero initial velocity. Falling objects happens to undergo constant acceleration (the acceleration of gravity), and so does your constantly accelerated car!

it takes 6 s to go a quarter mile (about 402.5m) with constant acceleration, no skidding

the equation d = vt (not d = at) is for objects moving with a constant velocity (zero acceleration). Your car's velocity is not constant, it starts from zero and increases constantly (constant acceleration).

Anything else that still puzzles you?

Isn't it wonderful that a falling apple and an accelerating car have something in common :) ?
 

FAQ: How High is the Coefficient of Static Friction for a Drag Car's Tires?

What is static friction?

Static friction is a force that prevents two surfaces from sliding against each other when there is no motion between them. It occurs when there is a force applied to an object, but the object does not move.

How is static friction different from kinetic friction?

Static friction is the force that keeps an object from moving, while kinetic friction is the force that slows down an object that is already in motion. Kinetic friction is typically weaker than static friction.

What factors affect the strength of static friction?

The strength of static friction depends on the types of surfaces in contact, the normal force between the surfaces, and any external forces acting on the object.

How do you calculate the force of static friction?

The force of static friction can be calculated using the formula Fs = μsN, where μs is the coefficient of static friction and N is the normal force. The coefficient of static friction is a constant that depends on the types of surfaces in contact.

How can static friction be reduced?

Static friction can be reduced by using lubricants, which create a slippery layer between the surfaces, or by increasing the temperature, which can decrease the coefficient of static friction. Another way to reduce static friction is by applying a greater external force on the object, which can overcome the force of static friction and cause the object to move.

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