- #1
ahsanmhamid
- 9
- 0
how high does a rocket have to go above the Earth's surface until its weight is 0.4 times its weight on the Earth's surface ? The radius of the Earth is 6.37 * 10 ^ 6m and the acceleration of gravity is 9.8 m/s^2. Answer in units of km.
what i got so far, i need help proceeding:
Applying the inverse-square law:
Final weight = 0.4 g = (1/2.5) g
The square root of 2.5 = 1.581
im stuck here, thanks :)
what i got so far, i need help proceeding:
Applying the inverse-square law:
Final weight = 0.4 g = (1/2.5) g
The square root of 2.5 = 1.581
im stuck here, thanks :)