- #1
-Dragoon-
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Thanks for all the help on the previous question, everyone. I appreciate it. I've got just another problem that has confused me.
Marian, who is standing on her balcony, is surprised by a pigeon and throws a flowerpot up in the air at 2.1m/s. It takes 3.0 seconds for the flowerpot to smash to the ground. The flowerpot experiences acceleration due to gravity of 9.81m/s^2 [down].
a) how high is Marian's balcony?
b) How fast was the flowerpot moving just before it smashed to the ground?
Delta d = V1(delta t) + 1/2(a)(delta t^2)
Delta d = V2(delta t) - 1/2(a)(delta t^2)
V2 ^2 = V1^2+2(a)(delta d)
a) part really confused me. I applied the first equation to find the distance:
d = 2.1m/s(3.0 seconds) +1/2(-9.81m/s^2 [down])(3.0^2)
d = 6.3 - 44.145
Now, unless she lives underground then I am clearly doing something wrong. If I were to apply the second equation, I would get a positive value but that only applies when there is a velocity final. This question has me completely stumped, I would like it if answerers could guide me through it by giving hints and not giving me the full answer.
For b part, I know that all I would need to apply is the third equation after finding the distance. But since the question states just before, would I use 2.9 as my change in time instead of 3.0 seconds which is when the pot hit the ground?
Thanks in advance for all the help.
Homework Statement
Marian, who is standing on her balcony, is surprised by a pigeon and throws a flowerpot up in the air at 2.1m/s. It takes 3.0 seconds for the flowerpot to smash to the ground. The flowerpot experiences acceleration due to gravity of 9.81m/s^2 [down].
a) how high is Marian's balcony?
b) How fast was the flowerpot moving just before it smashed to the ground?
Homework Equations
Delta d = V1(delta t) + 1/2(a)(delta t^2)
Delta d = V2(delta t) - 1/2(a)(delta t^2)
V2 ^2 = V1^2+2(a)(delta d)
The Attempt at a Solution
a) part really confused me. I applied the first equation to find the distance:
d = 2.1m/s(3.0 seconds) +1/2(-9.81m/s^2 [down])(3.0^2)
d = 6.3 - 44.145
Now, unless she lives underground then I am clearly doing something wrong. If I were to apply the second equation, I would get a positive value but that only applies when there is a velocity final. This question has me completely stumped, I would like it if answerers could guide me through it by giving hints and not giving me the full answer.
For b part, I know that all I would need to apply is the third equation after finding the distance. But since the question states just before, would I use 2.9 as my change in time instead of 3.0 seconds which is when the pot hit the ground?
Thanks in advance for all the help.