- #1
studentmom
- 12
- 0
The problem states:
A fireman is standing 50.0 m away from a burning building. He directs a stream of water from the fire hose at an angle of 30 degrees above the horizontal. If the initial speed is 40.0 m/s, at what height will the stream of water strike the building?
I understand that the velocity (40.0 m/s) needs to be broken down into its x- and y- components using sin and cos. I imagine that I need to find a time (in seconds) in order to get the vertical height. But I can't seem to figure out the equations to use and when to use them. The x-component of the velocity is 34.6 and the y-component is 20. I know that horizontal acceleration is zero and the vertical acceleration is -g.
Any help you can give is greatly appreciated.
Thanks!
A fireman is standing 50.0 m away from a burning building. He directs a stream of water from the fire hose at an angle of 30 degrees above the horizontal. If the initial speed is 40.0 m/s, at what height will the stream of water strike the building?
I understand that the velocity (40.0 m/s) needs to be broken down into its x- and y- components using sin and cos. I imagine that I need to find a time (in seconds) in order to get the vertical height. But I can't seem to figure out the equations to use and when to use them. The x-component of the velocity is 34.6 and the y-component is 20. I know that horizontal acceleration is zero and the vertical acceleration is -g.
Any help you can give is greatly appreciated.
Thanks!