How is √2 μ Interpreted Geometrically?

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In summary: I could be wrong, but it seems to me that this question could be answered much more easily (that is, intuitively) by thinking about the corresponding Riemann integral. It's a fact that if the function is Riemann integrable, then $$\int_{ \mathbb{R}^{2}} f \, dA = \int_{ \mathbb{R}^{2}} f \, d\mu.$$So take an example, and make $f$ really simple, say $f=1$. Then your integral is simply computing area. Your new measure, $\sqrt{2} \mu$, simply multiplies your area by $\sqrt{2}$,
  • #1
Juliayaho
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This is part 2 of a question... I already solved part 1 but I can't seem to be able to solve this one.
Interpret the measure √2 μ geometrically?

Any ideas... This is from real analysis class

Thanks in advance!
 
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  • #2
Re: Measure... Geometrically?

Juliayaho said:
This is part 2 of a question... I already solved part 1 but I can't seem to be able to solve this one.
Interpret the measure √2 μ geometrically?

Any ideas... This is from real analysis class

Thanks in advance!

What is \(\displaystyle \displaystyle \mu \) representing?
 
  • #3
Re: Measure... Geometrically?

The unique positive regular measure on B(R^2) such that for all f in C_c(R^2) λf= ∫_R^2 f dµ

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Prove It said:
What is \(\displaystyle \displaystyle \mu \) representing?

The unique positive regular measure on B(R^2) such that for all f in C_c(R^2) λf= ∫_R^2 f dµ

- - - Updated - - -

Juliayaho said:
The unique positive regular measure on B(R^2) such that for all f in C_c(R^2) λf= ∫_R^2 f dµ

- - - Updated - - -
The unique positive regular measure on B(R^2) such that for all f in C_c(R^2) λf= ∫_R^2 f dµ

λf=∫(from R to Riemann) f(tt)dt for all f in C_c(R^2).
 
  • #4
Re: Measure... Geometrically?

I could be wrong, but it seems to me that this question could be answered much more easily (that is, intuitively) by thinking about the corresponding Riemann integral. It's a fact that if the function is Riemann integrable, then
$$\int_{ \mathbb{R}^{2}} f \, dA = \int_{ \mathbb{R}^{2}} f \, d\mu.$$
So take an example, and make $f$ really simple, say $f=1$. Then your integral is simply computing area. Your new measure, $\sqrt{2} \mu$, simply multiplies your area by $\sqrt{2}$, since constants pull out of integrals (at least, they pull out of Riemann and Lebesgue integrals). What is going on geometrically for that to happen?
 
  • #5


Geometrically, the measure √2 μ represents the length of the diagonal of a square with side length μ. This can be visualized as the distance from one corner of the square to the opposite corner, forming a right triangle with sides μ and μ. The measure √2 μ can also be interpreted as the hypotenuse of this right triangle. This is a fundamental concept in geometry and is often used to find the length of diagonal lines in various shapes. In real analysis, this measure can be used to calculate the distance between two points on the coordinate plane or to determine the length of curves in calculus.
 

FAQ: How is √2 μ Interpreted Geometrically?

What is the definition of "Interpret Measure Geometrically"?

Interpret Measure Geometrically refers to the process of using geometric concepts and principles to measure and understand physical quantities and their relationships. This can involve measuring angles, lengths, areas, volumes, and other geometric properties of objects or systems.

How is geometry used to interpret measurements?

Geometry provides a framework for understanding and quantifying the physical world. By using geometric principles such as similarity, congruence, and proportionality, we can interpret measurements and make predictions about the behavior of objects and systems.

What are some common applications of interpreting measurements geometrically?

Interpreting measurements geometrically is used in a wide range of fields, including engineering, architecture, physics, and astronomy. Some common applications include calculating the volume of a container, determining the distance between two points, and analyzing the trajectory of a moving object.

Why is it important to interpret measurements geometrically?

Interpreting measurements geometrically allows us to make accurate and precise calculations and predictions about the physical world. It also helps us visualize and understand complex systems and phenomena, leading to advancements in technology and scientific understanding.

What are some challenges in interpreting measurements geometrically?

One challenge in interpreting measurements geometrically is obtaining accurate and precise data. This can be affected by factors such as human error, measurement tools, and environmental conditions. Additionally, interpreting measurements can become more complex when dealing with non-Euclidean geometries or high-dimensional systems.

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