How Is Average Force Calculated When Air Hits a Building?

In summary: Your Name]In summary, for this problem, the total impulse exerted on the building can be calculated by finding the mass of the air (3510kg) and multiplying it by the velocity of the air (30.55m/s). The average force exerted on the building can then be approximated by using a small time interval (dt) and the equation F = dp/dt.
  • #1
Morass
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Homework Statement



Air in a 110km/hr wind strikes head-on the face of a building 45m wide by 60m high and is brought to rest. If air has a mass of 1.3kg/m^3 calculate the average force exerted on the building.

Homework Equations



p = mv
delta P = Fav * t
dp/dt = F

The Attempt at a Solution



I know that the total impulse can be calculated by finding the total mass multiplied by the velocity. The mass is density multiplied by volume. But I'm unsure what the "volume" is in this case. Also, I am not sure how to relate the impulse to the average force as there is no time interval given. Should I be using differentials to represent very small amounts, namely dv and dt, to approach this problem?
 
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  • #2




Thank you for posting this interesting problem. Your approach using the equations for impulse and average force is a good start. In order to solve this problem, you will need to consider the volume of air that is hitting the building. In this case, the volume can be calculated by multiplying the height and width of the building (45m x 60m = 2700m^2).

Next, you will need to calculate the mass of the air that is hitting the building. As you correctly stated, mass is equal to density multiplied by volume. In this case, the density of air is given as 1.3kg/m^3 and the volume is 2700m^2. Therefore, the mass of the air is 3510kg.

Now, using the equation for impulse (p = mv), we can calculate the total impulse exerted on the building. The velocity of the air is given as 110km/hr, which is equivalent to 30.55m/s. Therefore, the total impulse is equal to 107,260.5 kg*m/s.

Finally, to calculate the average force exerted on the building, we can use the equation F = dp/dt. Since we do not have a specific time interval, we can use a very small time interval (dt) to approximate the average force. This can be represented by using differentials as you suggested. Therefore, the average force can be calculated as F = (dp/dt) = (107,260.5 kg*m/s)/(dt).

I hope this helps guide you in solving the problem. If you have any further questions or need clarification, please do not hesitate to ask. Keep up the good work in your studies!
 

FAQ: How Is Average Force Calculated When Air Hits a Building?

1. What is impulse?

Impulse is defined as the change in momentum of an object over a period of time. It is calculated by multiplying the force applied to an object by the time for which the force is applied.

2. How is momentum related to impulse?

Momentum is directly related to impulse. The change in momentum of an object is equal to the impulse applied to it.

3. How is impulse calculated in a problem?

To calculate impulse in a problem, you need to know the force applied to an object and the time for which the force is applied. The formula for impulse is Impulse = Force x Time.

4. What is the difference between impulse and force?

Impulse is the change in momentum of an object, while force is the push or pull applied to an object. Force is a vector quantity, while impulse is a scalar quantity.

5. How is the conservation of momentum applied in impulse problems?

The law of conservation of momentum states that the total momentum of a closed system remains constant. In impulse problems, this means that the total impulse applied to the system is equal to the change in momentum of the system.

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