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mugen715
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Homework Statement
This is the question:
2H1 + 3H1 ==> 4He2 + 1n0 +Q
Where Q = 17.7 MeV
The binding energy per nucleon are given below:
2H1 = 1.12 MeV
1n0 = Null
4He2 = 7.07 MeV
" Determine the binding energy per nucleon, in MeV, of tritium (3H1)"
Homework Equations
The Attempt at a Solution
This is how i do it,
The B.E for:
2H1 = 2 x 1.12 = 2.24 MeV
4He2 = 7.07 x 4 = 28.28 MeV
From chemical equation shown above, The energy before reaction is equal to energy after reaction. The energy is conversed before and after reaction:
2.24 + 3(X) = 28.28 MeV + 17.7 MeV
X = 14.58 MeV which is the B.E per nucleon for 3H1
But when i check up the answer, it turns out to be 2.78 MeV. What wrong with my method of solving the questions? can anyone explain what my mistake?