- #1
Badrakhandama
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1. The base of a cloud has an area of 2*10^7 metres squared and is on average 1km above the ground. treating the base of the cloud, the ground and the intervening air gap as a parallel plate capacitor, calculate the capacitance.[relative permittivity of air = 1.0]
2. I tried to say C = (Eo)(Er)(A)/(D)
And so, C = (8.85*10^-12)(1.0)(2*10^7)/(1000)
And this gives me C = 1.77*10^-7 Farads. However, the answer the book gives is 8.85*10^-9 Farads. Is the book wrong?
2. I tried to say C = (Eo)(Er)(A)/(D)
And so, C = (8.85*10^-12)(1.0)(2*10^7)/(1000)
And this gives me C = 1.77*10^-7 Farads. However, the answer the book gives is 8.85*10^-9 Farads. Is the book wrong?