- #1
damasgate
- 10
- 0
I know that H(t) = 1/a(t) x da/dt
I know that a(t) is proportional to t^2/3
and da/dt is proportional to a^-1/2
now H(t) should equal H(t) = a(t)^-1 x a(t)^-1/2
= a(t)^-3/2
= (t^2/3)^-3/2
= t^-1
However where is the constant 2/3 coming from? I can't find it anywhere in my calculations!
I know that a(t) is proportional to t^2/3
and da/dt is proportional to a^-1/2
now H(t) should equal H(t) = a(t)^-1 x a(t)^-1/2
= a(t)^-3/2
= (t^2/3)^-3/2
= t^-1
However where is the constant 2/3 coming from? I can't find it anywhere in my calculations!