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DaveTan
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Homework Statement
A single-turn square loop of side L is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1280 turns per meter and a diameter of 5.85 cm , and carries a current of 2.15 A .
Find the magnetic flux through the loop when L= 5.85 cm .
Homework Equations
Magnetic Field = 4pi *10^-7 * (Num loops/ length) * current
Magnetic Flux = Magnetic Field * Area * cos(theta)
The Attempt at a Solution
Magnetic Field = 4pi *10^-7 * (1280 loops/ 1.00m) * 2.15A = 0.003458T
Magnetic Flux = B * area = 0.003458 * 0.0585 * 0.0585 = 1.18x10-5
The answer is wrong, I would appreciate any help! Thanks!