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2 SO2 +O2 --> 2 SO3
A mixture of gases containing 0.20 mol of SO2 and 0.2 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC, what is the pressure in the flask after reaction is complete?
The answer key says the answer is 0.3(0.082)(298)/4, using PV = nRT. (0.3 being the number of moles of gas after the reaction.)
But according to the coefficients in the reaction, I thought since there are 0.2 moles of SO2 there should also be 0.2 moles of SO3.
Is it a typo or am I wrong in how I approached the question?
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