- #1
mcchoy528
Homework Statement
An airplane propeller is 2.78 m in length (from tip to tip) and has a mass of 127 kg . When the airplane's engine is first started, it applies a constant torque of 1880 N⋅m to the propeller, which starts from rest.
Part D
What is the average power output of the engine during the first 5.00 rev ?
Known:α=23.0rad/s2
ω after making 5.00rev=38.0rad/s
Work done by engine during first 5 rev=5.91kJ
Homework Equations
Pav= Work done/time
θ=ω0t +1/2αt2
The Attempt at a Solution
Since ω0=0,
θ=1/2αt2
t= √(2*5*2π/38.0)=1.65s
Pav= 5.91/1.65=3.58kW
I don't know why my answer is incorrect. Can anyone help?
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