- #1
BrainHurts
- 102
- 0
So let [itex]ℝ^{n}_{a}[/itex]={(a,v) : a [itex]\in[/itex] [itex]ℝ^{n}[/itex], v [itex]\in[/itex] [itex]ℝ^{n}[/itex]}
so any geometric tangent vector, which is an element of [itex]ℝ^{n}_{a}[/itex] yields a map
Dv|af = Dvf(a) = [itex]\frac{d}{dt}|_{t=0}[/itex]f(a+tv)
this operation is linear over ℝ and satisfies the product rule
Dv|a(fg) = f(a)Dvg + g(a)Dvf
if v|a = [itex]\sum_{i=1}^n[/itex] viei|a, then by the chain rule
Dv|af can be written as:
Dv|af [itex]\sum_{i=1}^n[/itex] vi [itex]\frac{∂f}{∂x_{i}}(a)[/itex]
not seeing how the chain rule applies and how the result as such.
so any geometric tangent vector, which is an element of [itex]ℝ^{n}_{a}[/itex] yields a map
Dv|af = Dvf(a) = [itex]\frac{d}{dt}|_{t=0}[/itex]f(a+tv)
this operation is linear over ℝ and satisfies the product rule
Dv|a(fg) = f(a)Dvg + g(a)Dvf
if v|a = [itex]\sum_{i=1}^n[/itex] viei|a, then by the chain rule
Dv|af can be written as:
Dv|af [itex]\sum_{i=1}^n[/itex] vi [itex]\frac{∂f}{∂x_{i}}(a)[/itex]
not seeing how the chain rule applies and how the result as such.