How is the EM-Force between current wires calculated in this problem?

In summary, the conversation discusses problem 105 in chapter 27 of Tipler and Mosca. It involves a long straight wire carrying a current of 20 A and a rectangular coil with sides of 5 cm and 10 cm, located 2 cm away from the wire, carrying a current of 5 A. The goal is to find the force on each segment of the coil and the net force on the coil. The equations B = (mu)*I/(2*pi*r) and F = BIL are used to solve the problem, with the final answers being F(2) = 100*10^-4N and F(4) = -0.286*10^-4N. It is noted that
  • #1
theperthian
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[SOLVED] EM-Force between current wires

Homework Statement



Problem 105 in chapter 27 Tipler and Mosca for those playing at home...

A long straight wire carries a current of 20 A, as shown in the figure. A rectangular coil
with 2 sides parallel to the straight wire has sides 5 cm and 10 cm with the near side at a
distance 2 cm from the wire. The coil carries a current of 5 A. (a) Find the force on each
segment of the rectangular coil due to the current in the long straight wire. (b) What is the
net force on the coil?

27-105.jpg


Homework Equations



good question
i used B= (mu)*I/(2*pi*r) [sorry, i can't use latex...]
and F=BIL

The Attempt at a Solution



The answers are F(2)= 100*10^-4N, F(4)= -0.286*10^-4N

For the two sides parallel (the 10cm ones),
I found B(a)=0.0002T
B(b)=0.0000571T
The other two wouldn't be effected cos they're perpendicular

F=BIL
F(a)=4*10^-4N
F(b)=1.14*10^-4N
...which are wrong

Is it something to do with the area and hence flux and shiznizzle?
 
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  • #2
wait a minute team, you would use different current values in the two equations, because one is the field due to one wire, and the second is the force on the other wire right?? ooooooooh, of course...

bahaha, got to love how i only solved it AFTER i posted it.
 

FAQ: How is the EM-Force between current wires calculated in this problem?

What is the EM-Force between current wires?

The EM-Force between current wires is a force that exists between two parallel wires carrying electric currents in the same direction. It is also known as the Ampere force or Laplace force.

How is the EM-Force calculated?

The EM-Force can be calculated using the formula F = μ0 * I1 * I2 * l / 2πd, where μ0 is the permeability of free space, I1 and I2 are the currents in the wires, l is the length of the wires, and d is the distance between the wires.

What is the direction of the EM-Force?

The direction of the EM-Force is perpendicular to both the direction of the currents and the line connecting the two wires. This means that the force will either attract or repel the wires depending on the direction of the currents.

How does the distance between the wires affect the EM-Force?

The EM-Force is inversely proportional to the distance between the wires. This means that as the distance increases, the force decreases. This relationship is known as the inverse-square law.

What are the practical applications of the EM-Force between current wires?

The EM-Force between current wires is used in various technologies such as electric motors, generators, and transformers. It is also a fundamental force in electromagnetics and is essential for understanding the behavior of electric currents and magnetic fields.

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