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Caesar_Rahil
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I have returned to this forum after six months.
How is the formula Kinetic Energy=1/2mv^2 derived?
How is the formula Kinetic Energy=1/2mv^2 derived?
Consider a particle moving from an initial point to a final point. Integrate [itex] \sum {\vec F } = m {\vec a } [/itex] over the trajectory. For the left hand side you getCaesar_Rahil said:I have returned to this forum after six months.
How is the formula Kinetic Energy=1/2mv^2 derived?
The formula for kinetic energy, KE=1/2mv^2, is derived from the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy. This means that the force applied to an object times the distance it moves is equal to the change in its kinetic energy. By rearranging this equation, we get KE=1/2mv^2.
The "m" in the formula represents the mass of the object, and "v" represents its velocity. The "KE" stands for kinetic energy, which is the energy an object possesses due to its motion.
The exponent 2 in the formula represents the squared value of the velocity. This is because kinetic energy is directly proportional to the square of an object's velocity. This means that as the velocity of an object increases, its kinetic energy increases exponentially.
Yes, the formula for kinetic energy can be used for objects of any mass and velocity. However, it is important to note that the velocity must be measured in meters per second (m/s) and the mass in kilograms (kg) for the formula to be accurate.
No, the formula for kinetic energy and potential energy are different. While kinetic energy is the energy an object possesses due to its motion, potential energy is the energy an object possesses due to its position or height. The formula for potential energy is PE=mgh, where "m" is the mass, "g" is the acceleration due to gravity, and "h" is the height of the object.