How Is the Mass of Each Hailstone Calculated?

[omc1]

Homework Statement

During a violent thunderstorm, hail the size of marbles (diameter = 2.2 cm) falls at a speed of 36 m/s. There are estimated to be 40 hailstones per cubic meter of air. Assume that, as for ice, 1 cm3 of hail has a mass of 0.92 g. What is the mass of each hailstone?

Homework Equations

volume of a sphere

The Attempt at a Solution

(4∏r^3)/3=5.58 x 0.92=5.13g x 40 stones=205.17g its not right for some reason even tho i used this number to solve the next problem and got that one right ...

 

[tiny-tim]

hi omc1!

What is the mass of each hailstone?
…
(4∏r^3)/3=5.58 x 0.92=5.13g x 40 stones=205.17g

erm … each hailstone!

 

[omc1]

oh duh!

 

[tiny-tim]

he he

 

[Nickie]

I would like to point out that the equation used to calculate the volume of a sphere is correct, but the value for the radius (r) should be 1.1 cm, not 2.2 cm. This is because the diameter (2.2 cm) is given, and the radius is half of the diameter. Additionally, the density of hail may vary and may not necessarily be the same as that of ice, so it is important to note that the mass of each hailstone may vary slightly. However, using the given information and assuming a density of 0.92 g/cm3, the estimated mass of each hailstone would be approximately 5.13 g.