How is the Schrödinger Equation Derived for a Particle in a Ring?

In summary, the Schrödinger equation for a particle inside a circle of radius R can be simplified using the symmetry of the problem. By taking the gradient in spherical form and setting r = R, θ = 90°, and ∅ = 0, the equation can be reduced to (d/dr)^2 + 1/r (d/dr) + 1/r^2 (d/dθ)^2. This simplification can also be achieved by considering the equation in cartesian coordinates in a plane.
  • #1
nokure
4
0

Homework Statement



Write down the Schrödinger equation for a particle inside a circle of radius R


Homework Equations



- Gradientψ(r,θ)=Eψ(r,θ)




The Attempt at a Solution



Take the gradient in spherical form and set r = R; θ=90;∅ as 0

Then you are left with the first two terms of the gradient where sin(90) = 1 and r = R.

I thought I was approaching this correctly but the solutions show this

(d/dr)^2 + 1/r (d/dr) + 1/r^2 (d/dθ)^2

I am not sure how are why you should get three three when the way I am thinking of it "phi" term will be zero.

Thanks for any help in advance!

Anand
 
Physics news on Phys.org
  • #2
1. Do you know how the SE looks like in cartesian coordinates in a plane ? (2 dimensions)
2. Can you use the symmetry of the problem to simplify the equation at 1. ?
 

FAQ: How is the Schrödinger Equation Derived for a Particle in a Ring?

What is the SE of a particle in a ring?

The SE (squared error) of a particle in a ring is a measure of the deviation of the particle's position from its expected or average position. It takes into account both the magnitude and direction of the deviation.

How is the SE of a particle in a ring calculated?

The SE of a particle in a ring is calculated by taking the square of the difference between the actual position of the particle and the expected or average position, and then summing these squared differences for all particles in the ring.

What does a high SE value mean for a particle in a ring?

A high SE value indicates that the particles in the ring are widely spread out and do not have a clear average position. This could be due to factors such as high energy or external forces acting on the particles.

Can the SE of a particle in a ring be negative?

No, the SE of a particle in a ring cannot be negative as it takes the square of the differences, resulting in a positive value. A negative SE value would not make physical sense in this context.

How is the SE of a particle in a ring used in scientific research?

The SE of a particle in a ring is a useful tool for analyzing and comparing experimental data. It can help identify patterns and trends in the behavior of particles and can also be used to assess the accuracy and reliability of experimental results.

Back
Top