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MickieDBaca
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1. The solid angle subtended by a 100 cm^2 circular detector at a distance of 1 m is ______steradians.
2. Ω = A/r^2 and A =∏r^2 (area of a circle)
3. I originally tried to find r by solving 100 = ∏r^2 and I got r = 5.6. I then tried to plug into the first equation for Ω only to realize that really, I had just gone in a circle and ended up with 4∏, which is the measure of sphere in steradians. Then I tried the tangent (5.6/100) to find the angle in degrees... The answer is .01 but I am unsure why...
2. Ω = A/r^2 and A =∏r^2 (area of a circle)
3. I originally tried to find r by solving 100 = ∏r^2 and I got r = 5.6. I then tried to plug into the first equation for Ω only to realize that really, I had just gone in a circle and ended up with 4∏, which is the measure of sphere in steradians. Then I tried the tangent (5.6/100) to find the angle in degrees... The answer is .01 but I am unsure why...
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