- #1
Adam Bourque
- 11
- 1
Given:
Rs = 0.20 Ω
R'r = 0.17 Ω
Xs = 0.50 Ω
X ' r = 0.60 Ω
Rc = 200 Ω
Xm = 15 Ω
Solution:
at Nr = 1165, slip = (Ns- Nr)/Ns = 0.02916 ~2.92%slip
at Nr = 1195, slip = (Ns- Nr)/Ns = 0.00416 ~0.42%slip
Zp = j Xm || ( (R'r / s) + j X'r )
therefore for i) slip s = 0.02916
Zp = 5.2787 <26.36' or 4.7295 + 2.344j
Ztotal = Zs + Zp = ( 0.2 + 0.5j) + (4.7295 + 2.344j) = 5.69<29.98'
What do the double vertical lines mean in this case, and how is the Zp equation solved? Please show work, thank you. Also how was that equation created? (Trying to study, thanks guys)
Rs = 0.20 Ω
R'r = 0.17 Ω
Xs = 0.50 Ω
X ' r = 0.60 Ω
Rc = 200 Ω
Xm = 15 Ω
Solution:
at Nr = 1165, slip = (Ns- Nr)/Ns = 0.02916 ~2.92%slip
at Nr = 1195, slip = (Ns- Nr)/Ns = 0.00416 ~0.42%slip
Zp = j Xm || ( (R'r / s) + j X'r )
therefore for i) slip s = 0.02916
Zp = 5.2787 <26.36' or 4.7295 + 2.344j
Ztotal = Zs + Zp = ( 0.2 + 0.5j) + (4.7295 + 2.344j) = 5.69<29.98'
What do the double vertical lines mean in this case, and how is the Zp equation solved? Please show work, thank you. Also how was that equation created? (Trying to study, thanks guys)