How Likely Is More Than Two Successes in Six Trials with 10% Success Rate?

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The discussion focuses on calculating the probability of achieving more than two successes in six trials, with a success rate of 10%. The formula P(x > 2) = 1 - P(x ≤ 2) is highlighted as the method to determine this probability. Participants emphasize the importance of understanding the problem and not relying solely on others for step-by-step solutions. There is a reminder to avoid posting repetitive questions in the forum. Overall, the conversation stresses the need for independent problem-solving skills in probability calculations.
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given trails n = 6, success probability p = 0.1



radou said:
P(x > 2) = 1 - P(x \leq 2)
P(x \leq 2) = \left( \begin{array}{c} 8 \\ 0 \end{array} \right) 0.3^0 (1-0.3)^{8-0} + \cdots (sum until x = 2, including that case)

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First, do not post same questions. Second, if you expect someone to solve the whole problem step by step (i.e. number by number), then you might be in the wrong forum. Third, without using your head, you won't solve any problem. Fourth, I'm not being rude.
 
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