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rlc
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Homework Statement
To help keep his barn warm on cold days, a farmer stores 859 kg of solar-heated water (Lf = 3.35E+5 J/kg) in barrels. For how many hours would a 2.02 kW electric space heater have to operate to provide the same amount of heat as the water does, when it cools from 11.3 to 0 °C and completely freezes?
Homework Equations
Q=mc(deltaTdegC)+mL
The Attempt at a Solution
Q=(859)(4187)(11.3)+(859)(335000)
Q=328406952 J
1kW=1000W=1000J/sec
1000t=328406952 J
t=328406 secs*1min/60secs*1hour/60mins=91 hours
But this is wrong. What am I missing?