- #1
ben-newton
- 3
- 0
Hi,
I have just started AS Physics and I am doing mechanics at the moment. I am stuck on a question at the moment which I would like to know if someone can answer:
A stone is dropped from rest from a diving board which is 6 metres above the water surface of the pool below. After it hits the water it sinks to the bottom of the pool (which is 4m deep) at a constant velocity equal to the velocity with whcih it struck the water.
How long does it take the stone to fall from the board to the water?
For this question I need to use one of the following formulas:
V= u + at
x= ut + 1/2 at^2
v^2= u^2 + 2ax
x=t/2 (u+v)
Can anyone help me?
Please?
(^2) = squared
I have just started AS Physics and I am doing mechanics at the moment. I am stuck on a question at the moment which I would like to know if someone can answer:
A stone is dropped from rest from a diving board which is 6 metres above the water surface of the pool below. After it hits the water it sinks to the bottom of the pool (which is 4m deep) at a constant velocity equal to the velocity with whcih it struck the water.
How long does it take the stone to fall from the board to the water?
For this question I need to use one of the following formulas:
V= u + at
x= ut + 1/2 at^2
v^2= u^2 + 2ax
x=t/2 (u+v)
Can anyone help me?
Please?
(^2) = squared