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TheDoorsOfMe
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Homework Statement
Ok, you have a cliff with height h and you launch a ball off of it at speed v and angle [tex]\theta[/tex]. How long till it hit the ground?
Homework Equations
(1) Vsin([tex]\theta[/tex]) = V[tex]_{y}[/tex]
(2) V[tex]_{f}[/tex] = V[tex]_{y}[/tex] + at
(3) d = ((V[tex]_{i}[/tex] + V[tex]_{f}[/tex])/2)*t
The Attempt at a Solution
Ok, so what I did was take equation (2) and set V[tex]_{f}[/tex]= 0. This alllows me to solve for the time that it takes to reach peak. Multiply this result by 2 to get the time when the ball is back to the plane of the cliff. Then for the time down to the ground I used equation (3) and plugged in V[tex]_{f}[/tex]= [tex]\sqrt{V^{2}_{i}+2gh}[/tex] for V[tex]_{f}[/tex]. Then I solved for t.
This lead to a result I feel looked to complicated for the question. Did I do this right?