- #1
nautica
A phonograph record slows from an initial 45 rpm at a rate of .05 rad/s^2.
a) how long does it take to come to rest?
orig rotational velocity = 45 rpm = 4.71 rad/sec
acc = -.05 rad/s^2
0 = 4.71 rad/s + (-.050 rad/s^2) t
t = 94.2 s
b) How many revolutions does it make before stopping?
(w + w)/2 = (4.71 rad/sec)/2 = 2.355 rad/s * 94.2 s = 221.84 rads =
35.31 rev
Last one for the week. How does this look?
Thanks agaiin
Nautica
a) how long does it take to come to rest?
orig rotational velocity = 45 rpm = 4.71 rad/sec
acc = -.05 rad/s^2
0 = 4.71 rad/s + (-.050 rad/s^2) t
t = 94.2 s
b) How many revolutions does it make before stopping?
(w + w)/2 = (4.71 rad/sec)/2 = 2.355 rad/s * 94.2 s = 221.84 rads =
35.31 rev
Last one for the week. How does this look?
Thanks agaiin
Nautica