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blimkie
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i need help with this problem
N.B. See eq. 13.26 and table 13.2 on p.382
11. [1pt] Zorch, an archenemy of Superman, decides to slow Earth's rotation to once per 29.0 h by exerting an opposing force at the equator and parallel to it. Although Superman knows that Zorch can only exert a force of 4.65×107 N (a little greater than a Saturn V rocket's thrust), he isn't sure if it is an immediate concern. Assuming that Earth's moment of inertia for such a process is 9.71×1037 kg·m2 and that its radius is 6.37×106 m, how long would Zorch have to push with this force to accomplish his nefarious goal?
Heres what i did so far..
here is the equation shown in the book a = T/I
a=angular acceleration
T=net torque
I=moment of inertia
so i determned the acceleration is 4.789x10^-31 m/s^2
then i used v=(2)(pi)(r)/T to find the veocity of Earth with the periods of rotation at 24 hours and 29 hours
v at 24h = 1.667x10^6 v at 29h = 1.379x10^6
so then i used the formula
Vf = Vf + a(t) i solved for t and my answer was 6.01 x10^35
when i entered my answer into the online homework grading system it was wrong and i have checked my work and ended up with the same answer twice so i guess I am just using the wrong approach
if anyone could help me that's great thanks
N.B. See eq. 13.26 and table 13.2 on p.382
11. [1pt] Zorch, an archenemy of Superman, decides to slow Earth's rotation to once per 29.0 h by exerting an opposing force at the equator and parallel to it. Although Superman knows that Zorch can only exert a force of 4.65×107 N (a little greater than a Saturn V rocket's thrust), he isn't sure if it is an immediate concern. Assuming that Earth's moment of inertia for such a process is 9.71×1037 kg·m2 and that its radius is 6.37×106 m, how long would Zorch have to push with this force to accomplish his nefarious goal?
Heres what i did so far..
here is the equation shown in the book a = T/I
a=angular acceleration
T=net torque
I=moment of inertia
so i determned the acceleration is 4.789x10^-31 m/s^2
then i used v=(2)(pi)(r)/T to find the veocity of Earth with the periods of rotation at 24 hours and 29 hours
v at 24h = 1.667x10^6 v at 29h = 1.379x10^6
so then i used the formula
Vf = Vf + a(t) i solved for t and my answer was 6.01 x10^35
when i entered my answer into the online homework grading system it was wrong and i have checked my work and ended up with the same answer twice so i guess I am just using the wrong approach
if anyone could help me that's great thanks