How Long Should Pilots Fire Engines for Safe Re-entry?

  • Thread starter pkhor
  • Start date
  • Tags
    Momentum
In summary, for the safe re-entry of a space capsule into Earth's atmosphere, the pilots must reduce their speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. With a backward force of 1.8 x 10^5 N and a mass of 3800 kg, they must fire their engine for 320 seconds to achieve this speed reduction. This can be calculated using the impulse-momentum theorem, where impulse equals force times change in time.
  • #1
pkhor
3
0
For a safe re-entry into the Earth's atmosphere, the pilots of a space capsule must reduce their speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. The rocket engine produces a backward force on the capsule of 1.8 x 10^5 N. The mass of the capsule is 3800 kg. For how long must they fire their engine? [Hint: Ignore the change in mass of the capsule due to the expulsion of exhaust gases.]

The answer to this problem is 320 seconds, but I have no idea how to get to that answer. I just want to know the formula or theorem that I can use to solve this specific problem. Your help would be highly appreciate.

PS. sorry for my English, I'm not a native speaker.
 
Physics news on Phys.org
  • #2
Newton's 2nd Law

[tex] \sum_{i=1}^{n} \vec{F}_{i} = \frac{d \vec{P}}{dt} [/tex]

Using [itex] \vec{p} = m \vec{v} [/itex]

[tex] \sum_{i=1}^{n} \vec{F}_{i} = \frac{d (m \vec{v})}{dt} [/tex]

The problem states mass is constant therefore it can go out of the derivative.

[tex] \sum_{i=1}^{n} \vec{F}_{i} = m \frac{d\vec{v}}{dt} [/tex]

For Finitessimals:

[tex] \sum_{i=1}^{n} \vec{F}_{i} = m \frac{\Delta \vec{v}}{\Delta t} [/tex]
 
  • #3
My course is Algebra based physics.
I can't understand Calculus, so is there any formula that based on algebra?
Thanks for your respond.
 
  • #4
pkhor said:
For a safe re-entry into the Earth's atmosphere, the pilots of a space capsule must reduce their speed from 2.6 x 10^4 m/s to 1.1 x 10^4 m/s. The rocket engine produces a backward force on the capsule of 1.8 x 10^5 N. The mass of the capsule is 3800 kg. For how long must they fire their engine? [Hint: Ignore the change in mass of the capsule due to the expulsion of exhaust gases.]

Use F=Ma to find the acceleration due to the backward force. You can then find the time needed to reduce their speed to the correct value.
 
  • #5
This problem involves manipulating the impulse-momentum theorem.
We know that Impulse is equal to the change in momentum (I=Δp) where change in momentum is Δp=mv(final)-mv(initial). We also know that Impulse is equal to Force*change in time (I=FΔt). Using these formulas you should be able to solve this question with ease.
 

FAQ: How Long Should Pilots Fire Engines for Safe Re-entry?

What is momentum?

Momentum is a physics concept that describes the quantity of motion an object has. It is calculated by multiplying an object's mass by its velocity.

How is momentum different from velocity?

Momentum and velocity are related, but they are different concepts. Velocity is a measure of how fast an object is moving in a specific direction, while momentum takes into account both an object's speed and its mass.

How do I calculate momentum?

Momentum can be calculated by multiplying an object's mass (m) by its velocity (v). This can be represented as p = m x v.

What is the unit of measurement for momentum?

The unit of measurement for momentum is kilogram-meters per second (kg·m/s).

How does momentum impact collisions?

Momentum plays a crucial role in collisions. According to the law of conservation of momentum, the total momentum of a closed system (such as two objects colliding) remains constant before and after the collision. This means that the combined momentum of the objects before the collision must equal the combined momentum after the collision.

Similar threads

Back
Top