- #1
RuthlessTB
- 22
- 0
Homework Statement
A ball is kicked with initial velocity 40 m/s at an angle of 37 degree above the horizontal. What is the time (in seconds) needed to reach the maximum height?
Homework Equations
Y-axis
h= Voy t - 0.5 g t^2
Vy= Voy - g t
Vy^2= Voy^2 - 2 g h
X-axis
d= Vox t
Vx= Vox
The Attempt at a Solution
I reached to a point where I couldn't figure out a way to continue..
I used this equation
h= Voy t - 0.5 g t^2
h= (40 sin(37)) t - 5 t^2
I have 2 unknowns..
I tried to use Vy=Voy - g t
to find the time, I got so far these 2 equations
h= (40 sin(37)) t - 5 t^2
0=(40 sin(37)) - 10 t
Is this right?