- #1
LeHotDoge
- 7
- 0
Homework Statement
Picture yourself in the castle of Helm's Deep from the Lord of the Rings. You are on top of the castle wall and are dropping rocks on assorted monsters that are 19.10 m below you. Just when you release a rock, an archer located exactly below you shoots an arrow straight up toward you with an initial velocity of 45.0 m/s. The arrow hits the rock in midair. How long after you release the rock does this happen?
Homework Equations
delta x = vot + at^2
v=vo+at
v^2=vo^2+2a(delta x)[/B]
The Attempt at a Solution
the initial velocity of the rock is 0, the acceleration of the rock is -9.8 m/s^2, the total displacement is -19.10 m.
delta x = vot + at^2
-19.10 = 0 + (-9.8)(t)^2
1.948 = t^2
t for rock =1.395 s
the initial velocity of the arrow is 45 m/s, the total displacement is 19.10m, and the acceleration is -9.8m/s^2
delta x = vot + at^2
19.10 = (45)(t) + at^2
19.10-45t=at^2
19.10-45=at
-25.9=(-9.8)(t)
2.642=t for arrow
t for arrow - t for rock = amount of time before they meet
2.642 s - 1.395 s = 1.247s