How long will it take to overtake

  • Thread starter joseph0205
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In summary, the two cars are traveling at 100km/hr and 95 km/hr, with lengths of 4.73 metres and a gap of 55.57 metres between them. With no acceleration, the faster car would need to gain 110 metres in order to overtake the slower car. Based on the given speeds, this would take approximately 22 seconds and cover a distance of 660 metres. The equation used to calculate this is the distance formula, d = vt, where d is the distance, v is the velocity and t is the time.
  • #1
joseph0205
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there a two cars, the one behind is traveling at 100km/hr, the one in front is traveling at 95 km/hr. say the car lengths are 4.73 metres and between the two cars is 55.57 metres. no acceleration for either cars.

will the car at the back be able to over take the other car within 2.1km?

could you also please show the equation you used, its for a physics assignment due monday thanks :)
 
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  • #2
joseph0205 said:
there a two cars, the one behind is traveling at 100km/hr, the one in front is traveling at 95 km/hr. say the car lengths are 4.73 metres and between the two cars is 55.57 metres. no acceleration for either cars.

will the car at the back be able to over take the other car within 2.1km?

could you also please show the equation you used, its for a physics assignment due monday thanks :)

I will explain with simpler numbers - you can repeat with the real values.

Make the cars 5m long, and the gap between them 50m

I am assuming that at first, the front of the fast car is 50m from the back of the slow car.
After overtaking, then moving back to his lane when the gap is again 50m, we now have the front of the fast car 60m in front of the slow car [so that the rear of the fast car is 50m in front of the slow car.
That means the fast car has to gain 110m

Convert those speeds to m/s and you get something like 25m/s and 30m/s [you can use the real numbers remember]
That means the fast car is gaining 5m each second.
To move up the 110 m that would take 22 seconds.

At 30m/s, the fast car will cover 660m in that time.

I chose easy numbers to use for explanation purposes. You need to use the real numbers in a similar way to see how far the cars travel during this manoeuvre.
 

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