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Vodkacannon
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Imagine a person is moving at the equator in the direction opposite of the Earth's spin. How long would it take them to stop the rotation of the Earth?
Assume:
the person's "weight" = 90.718 kg,
they person's speed = 1m/s,
The Earth's "weight" = 5.972*10^24 kg,
the angular velocity of the Earth = 7.292*10^-7 rad/s,
The radius of the Earth = 6.371*10^6 m,
and the inertia of the Earth = 8*10^37 kgm^2
Assume:
the person's "weight" = 90.718 kg,
they person's speed = 1m/s,
The Earth's "weight" = 5.972*10^24 kg,
the angular velocity of the Earth = 7.292*10^-7 rad/s,
The radius of the Earth = 6.371*10^6 m,
and the inertia of the Earth = 8*10^37 kgm^2
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