How Many Bananas to Power a Light Bulb?

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To determine how many bananas are needed to power a 100 W light bulb using the energy from potassium-40 decay, calculations begin with the average weight of a banana, which is 125 grams, yielding approximately 447.5 mg of potassium-40 per banana. The half-life of potassium-40 is 1.248 billion years, leading to a decay constant (k) of 5.55×10^-10. The energy released from the decay of potassium-40 must be calculated to find the total energy required to sustain the light bulb's power. The discussion emphasizes the need for an equation that incorporates the energy of decay to complete the solution. Ultimately, understanding the energy conversion from bananas to electrical energy is crucial for answering the original question.
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Homework Statement



If all of the energy from decay of the 40-K in one banana could be captured and converted into electrical energy, how many bananas would be needed to power a 100 W light bulb?

There is 358 mg potassium-K per 100 grams of banana

half life of potassium-40 is 1.248(3)×109 y

Homework Equations



ln(A/Ao)=-kt
e=mc2
k= (0.693/half-life)

The Attempt at a Solution



If a banana weighs 125 grams on average then there is 447.5 grams of potassium-40 in one banana.

(358)(1.25) = 447.5g
- - - - - - - - - - - - - -
k=(0.693/1.248(3)×10^9 y) = 5.55×10^-10

ln(A/Ao)=-kt
k = 5.55×10^-10
Ao = 447.5 g
t=?
 
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That's 447.5 mg of K-40

You'll need an equation that includes the energy of decay of the isotope.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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