How many drops per second keeps the protagonist awake? answer check

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In summary, your roommate, an aspiring novelist, asked for your opinion on a physics matter related to their novel. The central character is kept awake by a leaky faucet situated 19.6cm above the sink. With one drop leaving the faucet and another hitting the sink, and two more in between on the way down, the protagonist is kept awake. The question is how many drops per second are causing this disturbance, with no given equations to use. While there were some minor errors in labeling units, the final result is correct. One error was labeling 980ms^-2 instead of 980cms^-2, and another was calculating frames per second with a dimension of s^-1.
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negation
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Homework Statement



Your roommate is an aspiring novelist and asks your opinion on a matter of physics. The novel's central character is kept awake at night by a leaky faucet. The sink is 19.6cm below the faucet. At the instant one drop leaves the faucet, another strikes the sink below and two more are in between on the way down. How many drops per second are keeping the protagonist awake?

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The Attempt at a Solution



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  • #2
You had a couple of slips in labeling units correctly, but that did not affect the final result, which is correct.
 
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  • #3
voko said:
You had a couple of slips in labeling units correctly, but that did not affect the final result, which is correct.

Like where 980ms^-2 should be 980cms^-2.
 
  • #4
That is one.

Another is where you calculate how many frames you have in one second. Obviously, the dimension of that is s-1.
 
  • #5


To calculate the number of drops per second, we need to know the time it takes for a drop to travel from the faucet to the sink. This can be calculated using the equation d = 1/2gt^2, where d is the distance (19.6cm), g is the acceleration due to gravity (9.8 m/s^2), and t is the time. Solving for t, we get t = √(2d/g) = √(2*0.196/9.8) = 0.2 seconds.

Since there are 4 drops in this time period, the number of drops per second is 4/0.2 = 20 drops per second. This means that 20 drops are hitting the sink every second, keeping the protagonist awake. However, this number may vary depending on the size of the drops and the rate at which they are dripping from the faucet.
 

FAQ: How many drops per second keeps the protagonist awake? answer check

How many drops per second should be used to keep the protagonist awake?

The exact number of drops per second varies depending on the individual's tolerance and sensitivity to sound. However, on average, 1-2 drops per second are recommended to keep the protagonist awake.

2. Is there a specific type of liquid that is more effective in keeping the protagonist awake?

There is no scientific evidence to suggest that a specific type of liquid is more effective in keeping someone awake. However, liquids that are more acidic or have a strong smell may be more irritating and therefore more effective in keeping someone awake.

3. How long should the drops be administered to keep the protagonist awake?

The duration of the drops should vary and not be consistent to prevent the protagonist from getting used to the sound and falling asleep. It is recommended to administer drops for 5-10 minutes at a time, with breaks in between.

4. Can the drops per second method be harmful to the protagonist?

The drops per second method is not considered harmful, but it can be uncomfortable and irritating for the individual. It is important to monitor the individual's response and stop immediately if they experience any discomfort or adverse effects.

5. Is this method scientifically proven to keep someone awake?

While there is no specific scientific research on the drops per second method, the concept is based on the idea that the sound of dripping liquid can be irritating and disrupt sleep. This method may work for some individuals, but it is not a guaranteed or scientifically proven method to keep someone awake.

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