How Many Electrons Are Transferred in a 450V Capacitor?

In summary, a capacitor with a capacitance of 2.5x10^-8F has a potential difference of 450v during the charging process. Using the equation C=qV and the charge of one electron being approximately 1.6x10^-19C, it can be determined that approximately 1.56x10^11 electrons have been transferred.
  • #1
Geophysicist
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Homework Statement


A capacitor has a capacitance of 2.5x10-8F. In charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 450v, hoow many electrons have been transferred?


Homework Equations


C=qV


The Attempt at a Solution


C=qV
q=C/V
q=2.5x10-8/450
 
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  • #2


So far so good, now how would you convert from a charge q to a number of electrons? (Hint: what's the charge of one electron?)
 
  • #3


charge of one electron is approximately 1.6x10^-19C. divide q by the charge for one electron.
 

FAQ: How Many Electrons Are Transferred in a 450V Capacitor?

How is potential difference between two plates measured?

The potential difference between two plates is measured using a voltmeter, which is connected in parallel to the plates. The voltmeter measures the voltage or potential difference in volts (V).

What is the unit of potential difference?

The unit of potential difference is volts (V). This is a derived unit in the International System of Units (SI) and is equivalent to one joule per coulomb (J/C).

How is potential difference related to electron transfer?

Potential difference, also known as voltage, is directly proportional to the number of electrons that are transferred between two points. This means that the higher the potential difference, the greater the number of electrons transferred.

Can potential difference be negative?

Yes, potential difference can be negative. This occurs when the direction of electron flow is opposite to the direction of conventional current flow. In such cases, the potential difference is denoted with a negative sign.

What is the formula for calculating electron transfer based on potential difference?

The formula for calculating electron transfer based on potential difference is Q = CV, where Q is the charge transferred in coulombs, C is the capacitance in farads, and V is the potential difference in volts. This formula is known as the charge-voltage relationship in electrical circuits.

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