ENE said:
ENE said:
ENE said:voltage across the capacitor
how we get exponential here?
fizzle said:
ENE, that's an awfully basic equation, you needn't worryVanadium 50 said:
ENE said:
The static electric field is a conservative field. So the work done on a closed path is zero.ENE said:
To calculate the number of electrons on a capacitor, you need to know the capacitance of the capacitor (in Farads) and the voltage applied to it. Then, use the formula Q = CV, where Q is the charge in Coulombs and C is the capacitance. Finally, since one electron has a charge of 1.6 x 10^-19 Coulombs, divide the total charge by this value to get the number of electrons.
The number of electrons on a capacitor is directly proportional to its capacitance. This means that as the capacitance increases, the number of electrons on the capacitor also increases. Similarly, as the capacitance decreases, the number of electrons decreases.
The number of electrons on a capacitor can change if the voltage applied to it changes. This is because the capacitance remains constant, but the charge on the capacitor changes according to the formula Q = CV. So, as the voltage changes, the number of electrons on the capacitor also changes.
The number of electrons on a capacitor directly affects its energy storage capacity. In fact, the energy stored in a capacitor is directly proportional to the square of the number of electrons on it. This means that the more electrons a capacitor has, the more energy it can store.
To convert the number of electrons on a capacitor into its equivalent capacitance, you can use the formula C = Q/V, where C is capacitance in Farads, Q is the charge in Coulombs, and V is the voltage. Simply plug in the number of electrons for Q and the given voltage, and you will get the equivalent capacitance in Farads.