How many six-letter words (not necessarily with sense) composed of 4 different

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The discussion revolves around calculating the number of six-letter words formed from four different consonants and two different vowels using the English alphabet. Participants question whether letter repetition is allowed and if nonsensical combinations, like "cdvowu," are acceptable. Clarification is sought on whether the inquiry pertains to all possible combinations or specific chosen letters. One contributor expresses concern that another user has posted multiple assignments without attempting to solve them first. The conversation emphasizes the importance of demonstrating thought processes in problem-solving.
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How many six-letter words (not necessarily with sense) composed of 4 different consonants and 2 different vowels can be formed from the English Alphabet?
 
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Are you allowing repeating of the letters? By sense are you allowing "cdvowu" as a word? if those were your 6 letters? Are you wanting to know all possible combinations or just for those specific 6 letters?
 
so i had answered this, and then realized this poster had put all of their assignments on here, without thinking about them or attempting to do them. so, i'll help after diceyfume shows us his attempts at solving this problem and his thought proceses.
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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