- #1
Yankel
- 395
- 0
Hello all,
I am struggling with this relatively simple task.
In a university with 88 students, each student can choose to participate in 3 afternoon activities: activity A, activity B and activity C. Each student can choose to participate in some activities, all or none.
33 students participate in activity A
28 students participate in activity B
33 students participate in activity C
14 students participate in activity A and B
18 students participate in activity A and C
10 students participate in activity B and C
6 students participate in activity A, B and C
1. How many students decided not to participate in any activity ?
2. How many students participate ONLY in activity A ?
3. How many students participate in activity A OR B, but NOT in C ?
I think I did "1" OK, I got that the answer is 30 (am I correct ?).
I solved it using union and intersection, and using the rule of union of 3 sets.
I find it hard to solve "2" and "3".
I am struggling with this relatively simple task.
In a university with 88 students, each student can choose to participate in 3 afternoon activities: activity A, activity B and activity C. Each student can choose to participate in some activities, all or none.
33 students participate in activity A
28 students participate in activity B
33 students participate in activity C
14 students participate in activity A and B
18 students participate in activity A and C
10 students participate in activity B and C
6 students participate in activity A, B and C
1. How many students decided not to participate in any activity ?
2. How many students participate ONLY in activity A ?
3. How many students participate in activity A OR B, but NOT in C ?
I think I did "1" OK, I got that the answer is 30 (am I correct ?).
I solved it using union and intersection, and using the rule of union of 3 sets.
I find it hard to solve "2" and "3".