- #1
2h2o
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- 0
Homework Statement
How many types of protons are present?
Homework Equations
compound 1:
CH3CH2OCH2CH2CH2CH2CH3
and
compound 2:
CH3CH2CO2CH2CH3
The Attempt at a Solution
Compound 1:
Arbitrarily assigning hydrogens which see a unique environment, left to right as appropriate.
CH3(A)CH2(B)OCH2(C)CH2(D)CH2(D)CH2(E)CH3(A)
My solutions manual claims that there are seven types of 1H in this molecule. I was under the impression that the high electron affinity of the oxygen will only deshield atoms ~1 sigma bond away. Is this impression false?
Compound 2:
First of all, this structural formula appears to me to describe an impossible molecule. Neither O atom has enough bonds to satisfy their "octet", yet to meet this criteria would require an isomer.
Moreover, even if I draw this out as described, using the method above:
CH3(A)CH2(B)CO2CH2(B)CH3(A)
Noting the symmetry of the molecule, I see two types of 1H, but my solutions manual claims four.
Where am I going wrong?