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cronuscronus
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Hi all. I was hoping somebody could help me with my reasoning here? This is a twist on a typical balls and bins problem.
How many ways are there to pick a collection of 10 coins from piles of pennies, nickels, dimes, quarters, and half-dollars? Base on the following condition:
a) Assuming that each pile has at least 10 or more coins.
14choose4 options. So 1001 ways to pick a collection of 10 coins.
b) Assuming that each pile has at least 10 or more coins and the pick must consist of at least one quarter coin or at least one dime.
14choose4 - 12choose10 = 1001 - 66 = 935
c) There are only 8 coins in each pile.
11choose4 = 330
d) There are only 8 coins in each pile and the pick must have at least one penny and two nickels?
11choose4 - 1 = 329
How many ways are there to pick a collection of 10 coins from piles of pennies, nickels, dimes, quarters, and half-dollars? Base on the following condition:
a) Assuming that each pile has at least 10 or more coins.
14choose4 options. So 1001 ways to pick a collection of 10 coins.
b) Assuming that each pile has at least 10 or more coins and the pick must consist of at least one quarter coin or at least one dime.
14choose4 - 12choose10 = 1001 - 66 = 935
c) There are only 8 coins in each pile.
11choose4 = 330
d) There are only 8 coins in each pile and the pick must have at least one penny and two nickels?
11choose4 - 1 = 329
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