- #1
jack1234
- 133
- 0
There are 6 white and 5 black ball. How many ways to choose 2 balls from it?
My Answer:
3 ways, which is
(1)two white ball
(2)One white and One Black
(3)Two Black ball
What is the probability that one of the drawn balls is white and the other black?
My Answer:
C(6,1)*C(5,1)/C(11,2)
If my answer for this two question is correct, can I conclude that, for combination, we view all black ball as identical,
but for the sample space of probability(if we view it as unordered set of drawn balls) we treat all the black balls as distinct, hence we have C(11,2)?
My Answer:
3 ways, which is
(1)two white ball
(2)One white and One Black
(3)Two Black ball
What is the probability that one of the drawn balls is white and the other black?
My Answer:
C(6,1)*C(5,1)/C(11,2)
If my answer for this two question is correct, can I conclude that, for combination, we view all black ball as identical,
but for the sample space of probability(if we view it as unordered set of drawn balls) we treat all the black balls as distinct, hence we have C(11,2)?