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algebra 2 combinations
The number of possible combinations can be calculated using the combination formula, which is nCr = n! / (r! * (n-r)!). In this case, n = 5 (total number of cards) and r = 3 (number of kings). So the number of combinations is 5C3 = 5! / (3! * (5-3)!) = 10.
The probability can be calculated by dividing the number of combinations that result in 3 kings and 2 queens by the total number of possible combinations. In this case, the probability is 10/52 = 0.1923 or approximately 19.23%.
Yes, it is possible. Since there are 4 kings and 4 queens in a standard deck of 52 cards, there are enough cards to make a combination of 3 kings and 2 queens.
If order does not matter, the combinations are considered as combinations without replacement, which means the same set of cards cannot be counted more than once. In this case, the number of combinations can be calculated using the combination formula as shown in question 1, and the result is 10.
In this scenario, a combination refers to the selection of 5 cards without considering the order in which they are picked, while a permutation would consider the order in which the cards are picked. For example, a combination of 3 kings and 2 queens could be (K, K, K, Q, Q), while a permutation could be (K, K, Q, Q, K) or (K, Q, Q, K, K). The number of permutations would be greater than the number of combinations, as the order of the cards is important in permutations.