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TFM
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[SOLVED] Gas Laws Problem
A steel tank is completely filled with 2.90 metres cubed of ethanol when both the tank and the ethanol are at a temperature of 33.5 degrees Celsius.
When the tank and its contents have cooled to 16.5 degrees Celsius, what additional volume of ethanol can be put into the tank?
[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} [/tex]
Thus
[tex] \frac{V_1*T_2}{T_1} = V_2[/tex]
Thus [tex]V_1-V_2=\Delta V[/tex]
Converting the Temperatures into Kelvin, I get:
[tex]\frac{289.65*2.9}{306.65}[/tex]
This gives a volume of 2.739, and a change in volume of 0.16, but apparently this is incorrect?
TFM
Homework Statement
A steel tank is completely filled with 2.90 metres cubed of ethanol when both the tank and the ethanol are at a temperature of 33.5 degrees Celsius.
When the tank and its contents have cooled to 16.5 degrees Celsius, what additional volume of ethanol can be put into the tank?
Homework Equations
[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} [/tex]
Thus
[tex] \frac{V_1*T_2}{T_1} = V_2[/tex]
Thus [tex]V_1-V_2=\Delta V[/tex]
The Attempt at a Solution
Converting the Temperatures into Kelvin, I get:
[tex]\frac{289.65*2.9}{306.65}[/tex]
This gives a volume of 2.739, and a change in volume of 0.16, but apparently this is incorrect?
TFM