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munkachunka
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extra power required to maintain the same speed on an incline
a tank of 80 metric tonnes is traveling at a uniform speed of 54km/r on level terrain, it the starts traveling uphill on an incline of 1 in 10 sine slope)
Calculate the extra power required from the engine in Megawatts to maintain the same speed on the incline.
F=M*A
P=F*V
F=(% grade of hill)*M*G
I calculated the power required to go uphill as
F=1/10 * 80000*9.8 = 78400N
therefore power = F*V = 78400*15m/s = 1.176MW
the problem I have is that I can't seam to find an equation to work out the force on the flat which does not have the acceleration variable, do I just put this to 1 and solve that way? which would give a force of 784000N, P=F*V = 784000*15 = 11760000.
take the first answer away from the second which leave a difference in power of 10.584MW.
Really not too sure.
I know of other equations such as Ek=1/2Mv^2 for power to accelerate a vehicle but don't think this is the equation to use,
Homework Statement
a tank of 80 metric tonnes is traveling at a uniform speed of 54km/r on level terrain, it the starts traveling uphill on an incline of 1 in 10 sine slope)
Calculate the extra power required from the engine in Megawatts to maintain the same speed on the incline.
Homework Equations
F=M*A
P=F*V
F=(% grade of hill)*M*G
The Attempt at a Solution
I calculated the power required to go uphill as
F=1/10 * 80000*9.8 = 78400N
therefore power = F*V = 78400*15m/s = 1.176MW
the problem I have is that I can't seam to find an equation to work out the force on the flat which does not have the acceleration variable, do I just put this to 1 and solve that way? which would give a force of 784000N, P=F*V = 784000*15 = 11760000.
take the first answer away from the second which leave a difference in power of 10.584MW.
Really not too sure.
I know of other equations such as Ek=1/2Mv^2 for power to accelerate a vehicle but don't think this is the equation to use,
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