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Homework Statement
(c) A standard aluminium ingot is 746 mm in length at 20°C. When the ingots reach a temperature of 500°C. Calculate:(ii) the induced force in an ingot assuming it has become jammed in the furnace and is NOT free to expand
y = Modulus of elasticity for aluminium: 69 GPa
A=0.019m^2
Change in length= 7.95mm
Original Length=740mm
Homework Equations
F=Ay(change in length / original length)
The Attempt at a Solution
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F=0.019*69x10^9(7.95/740)
F=14084391 Newtons
I've been to solve the above and have been told my original answer was incorrect. I've relooked at my work and come up with the above.
Any helps as to whether this looks correct would be greatly appreciated.
Thanks