How Much Heat is Lost from a Swimming Pool?

[purehavoccc]

woudl anyone know how to do this by any chance?

The temperature of a swimming pool is 32ºC at 2 p.m. in the afternoon. At 6 p.m., its temperature decreases to 26ºC. Given the pool contains 1200 liters of water and water’s specific heat is 4.186 J/gºC. How much heat does the pool lose to the atmosphere in 4 hours? (Assume 1 lit = 1 kg.)

50.208 J

40.116 J

286800000 J

5776800000 J

57768 J

i have no clue as to which one it is and i need to turn in this exam soon =/
thanks alot, i just need a little help.

 

[Stevedye56]

use waters density to find out how many grams of H20 you have then use
q=mvdeltaT to find q.

Hope this helps.

 

[Blueshift5]

Based on the information provided, we can calculate the amount of heat lost from the swimming pool using the formula Q = m x c x ΔT, where Q is the heat lost, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.

First, we need to convert the volume of water from liters to kilograms. Since 1 liter is equal to 1 kilogram, the mass of water in the pool is also 1200 kg.

Next, we can calculate the change in temperature by subtracting the initial temperature (32ºC) from the final temperature (26ºC). This gives us a change of 6ºC.

Plugging in these values into the formula, we get Q = (1200 kg) x (4.186 J/gºC) x (6ºC) = 30,000 J.

Therefore, the swimming pool loses 30,000 J of heat to the atmosphere in 4 hours. This corresponds to the answer option of 286800000 J, which is in joules (J).