- #1
mathdad
- 1,283
- 1
Rita wants to cover a roughly rectangular area with netting. The height is 9 feet (but one side is along a solid fence, so could be 4 feet), two sides are each 6 feet, and the other side is 5_1/2 feet. How much netting does she need? Netting comes as a rectangular or square piece.
My Work:Let A = rectangular surface area Use the formula: A = 2(wh + Lh + Lh) Rewrite 5_1/2 as 11/2 for easy calculation. If the height is 9 feet, use the following set up: A = 2[(11/2)(9) + (6)(9) + (6)(9)] If the height is 4 feet, use the following set up: A = 2[(4)(9) + (6)(9) + (6)(9)]
Is any of this right?
My Work:Let A = rectangular surface area Use the formula: A = 2(wh + Lh + Lh) Rewrite 5_1/2 as 11/2 for easy calculation. If the height is 9 feet, use the following set up: A = 2[(11/2)(9) + (6)(9) + (6)(9)] If the height is 4 feet, use the following set up: A = 2[(4)(9) + (6)(9) + (6)(9)]
Is any of this right?