- #1
jimmyboykun
- 39
- 0
Homework Statement
Converting the energy of one food calorie into mechanical energy, starting from rest, to what speed could you accelerate a 133-lbs person?
Homework Equations
1 calorie= 4.184J
1 lbs= 0.453592kg
K=1/2mv^2
The Attempt at a Solution
here what I did, I converted the lbs to kg which was 60.33kg. I was under the impression to use kinetic energy.
4.184J=1/2(60.33kg)v^2
4.184J/30.165kg=v^2
sqrt 4.184J/30.165kg= 0.372m/s
This is how I solved my problem, but I got 1 out of 10. Can someone explain to me what I did wrong?