- #1
Jahnavi
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Homework Statement
The temperature of 100 gm of water is to be raised from 24°C to 90°C by adding steam to it .Calculate the mass of the steam required for this purpose .
Homework Equations
Latent heat of vaporisation of steam = 540 Cal/g
The Attempt at a Solution
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Let 'm' be the mass of steam added.
Heat released by steam as it condenses into
water = 540m
Heat released by condensed water as it moves
from 100°C to 90°C = mx1x10 = 10m
Total heat released = 540m+10m= 550m
Heat required by 100gm water to raise its temp from
24°C to 90°C = 100x1x66
Equating the two , 550m = 6600
m = 12gm
Is it correct ?