- #1
HellgY
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A boat floats across this river, and back,
It takes 5 hours for it to reach point B, from point A, and then 7 hours to
return to point to point A from point B.
Naturally it's because not because the crew got tired on the way back,
but because the flow of the river, or it's angle which is pretty much more of the same.
the question is: How much time will it take for a log to arrive from point A, to point B?.
I believe the V0=Constant(The flow), otherwise that teacher would have said mentioned it.
i believe the equation is:
T2/V1=T1/V1-V0
The equation with all the numbers intact should look like that:
7/x=5/x-y
and there is another equation i can add, based upon the fact that the distances AB, and BA are the same.
T1*V1=T2*(V1-V0)
5x=7x-7y
does anyone have a clue how can i sole this correctly?, because my solution just doesn't seems correct at all.
{7/x=5/x-y
{5x=7x-7y*
or is it:
{5x=7x-yx
{x-y=5x/7*
It takes 5 hours for it to reach point B, from point A, and then 7 hours to
return to point to point A from point B.
Naturally it's because not because the crew got tired on the way back,
but because the flow of the river, or it's angle which is pretty much more of the same.
the question is: How much time will it take for a log to arrive from point A, to point B?.
I believe the V0=Constant(The flow), otherwise that teacher would have said mentioned it.
i believe the equation is:
T2/V1=T1/V1-V0
The equation with all the numbers intact should look like that:
7/x=5/x-y
and there is another equation i can add, based upon the fact that the distances AB, and BA are the same.
T1*V1=T2*(V1-V0)
5x=7x-7y
does anyone have a clue how can i sole this correctly?, because my solution just doesn't seems correct at all.
{7/x=5/x-y
{5x=7x-7y*
or is it:
{5x=7x-yx
{x-y=5x/7*
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